Two organic compounds 'X' and 'Y' which contain carbon and hydrogen only, have vapour densities of 13 and 39 respectively. The molecular formula of 'X' and 'Y' are:
$[C = 12, H = 1]$

X =

C H_{4}; Y = C_{6} H_{6}

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X =

C_{6} H_{8}; Y = C_{2} H_{2}

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X =

C_{2} H_{6}; Y = C_{6} H_{6}

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X =

C_{2} H_{2}; Y = C_{6} H_{6}

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Solution

The correct option is C X = $C_{2} H_{2}; Y = C_{6} H_{6}$
As we know,
molar mass $= 2 \times v a p o u r d e n s i t y$
molar mass of X $= 2 \times 13 = 26 g m$
$X = C_{2} H_{2}$
molar mass of Y $= 39 \times 2 = 78 g m$
$Y = C_{6} H_{6}$

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Two organic compounds 'X' and 'Y' which contain carbon and hydrogen only, have vapour densities of 13 and 39 respectively. The molecular formula of 'X' and 'Y' are:[C=12,H=1]

The correct option is C X = C2H2;Y=C6H6As we know,molar mass =2×vapour densitymolar mass of X =2×13=26 gmX=C2H2molar mass of Y =39×2=78 gmY=C6H6

Two organic compounds 'X' and 'Y' which contain carbon and hydrogen only, have vapour densities of 13 and 39 respectively. The molecular formula of 'X' and 'Y' are:
$[C = 12, H = 1]$

The correct option is C X = $C_{2} H_{2}; Y = C_{6} H_{6}$
As we know,
molar mass $= 2 \times v a p o u r d e n s i t y$
molar mass of X $= 2 \times 13 = 26 g m$
$X = C_{2} H_{2}$
molar mass of Y $= 39 \times 2 = 78 g m$
$Y = C_{6} H_{6}$