Question

Two oscillating systems; a simple pendulum and a vertical spring - mass - system have same time period of motion on the surface of the Earth. If both are taken to the moon, then

• A. Time period of the simple pendulum will be more than that of the spring - mass system
• B. Time period of the simple pendulum will be equal to that of the spring - mass system
• C. Time period of the simple pendulum will be less than that of the spring - mass system
• D. Nothing can be said definitely without observation

Answer 1

The correct option is A

Time period of the simple pendulum will be more than that of the spring - mass system

For simple pendulum: $T=2\pi \sqrt{\frac{l}{g}}$

As g is less on moon, time period will be more

For spring mass system: $T=2\pi \sqrt{\frac{m}{K}}$

Since it does not depend on acceleration due to gravity, it will not change.