Question

two oxides of metal contains 50% and 40% metal M respectively. if the formula of first oxide is MO₂ the formula os second oxide will b
a)MO₂
b)MO₃
c)M₂O
d)M₂O₅

Answer 1

First metal = 50 %
Hence , oxygen percentage = 50 %
Formula of first oxide = MO₂
Second metal = 40 %
Hence , percentage of oxygen = 60 %
${\text{M}}_{\frac{4}{5}}{\text{O}}_{2\times \frac{6}{5}}$ = MO₃
Formula will be MO₃ of the second oxide.