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Byju's Answer

Standard XII

Chemistry

Ionization Enthalpy

Two p-block e...

Question

Two p-block elements $x$ (outer configuration $n s^{2} n p^{3}$ ) and $z$ (outer configuration $n s^{2} n p^{4}$ ) occupy neighbouring positions in a period. Using this information which of the following is correct with respect to their ionization potential $I_{x}$ and $I_{z}$ .

I_{x} > I_{z}

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I_{z} > I_{x}

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I_{z} = I_{x}

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Relation between

I_{x}

and

I_{z}

is uncertain.

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Solution

The correct option is A $I_{x} > I_{z}$
Element $x$ has a stable half-filled electronic configuration. Therefore due to its stable electronic configuration, $I_{x} > I_{z}$ .

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Two thin identical rods are arranged along X-axis and Y-axis with their ends meeting at the origin. If $I_{x}, I_{y} a n d I_{z}$ are the moments of inertia of the system about the X, Y and Z axes respectively, then which of the following are correct?

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Two p-block elements x (outer configuration ns2np3) and z (outer configuration ns2np4) occupy neighbouring positions in a period. Using this information which of the following is correct with respect to their ionization potential Ix and Iz.

The correct option is A Ix>IzElement x has a stable half-filled electronic configuration. Therefore due to its stable electronic configuration, Ix>Iz.

Two p-block elements $x$ (outer configuration $n s^{2} n p^{3}$ ) and $z$ (outer configuration $n s^{2} n p^{4}$ ) occupy neighbouring positions in a period. Using this information which of the following is correct with respect to their ionization potential $I_{x}$ and $I_{z}$ .

The correct option is A $I_{x} > I_{z}$
Element $x$ has a stable half-filled electronic configuration. Therefore due to its stable electronic configuration, $I_{x} > I_{z}$ .