Question

two painters were painting a house.X finished hiswork in 10 days.thesame amount of work was done by painter Y in 12 days.how much more work does painter X do in a day than painter Y

Answer 1

Let the total work be 1

Then,Time taken by painter X to do 1 work=10 days

And the time taken by painter Y to do 1 work=12 days

Then, work done by painter X in 1 day$=\frac{1}{10}$

And work done by painter Y in 1 day$=\frac{1}{12}$

Then the work which is done more by painter X than painter Y in 1 day =$\frac{1}{10}-\frac{1}{12}=\frac{1}{60}=0.167$ (approx.)