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Question

Two paper screens A and B are separated by a distance of 100 m. A bullet pierces A and then B. The hole in B is 10 cm below the hole in A. If the bullet is travelling horizontally at the time of hitting the screen A, calculate the velocity of the bullet when it hits the screen A. Neglect the resistance of paper and air.
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Solution

Equation of motion in x-direction, 100=v×t
t=100v ............(i)
In ydirection
0.1=1/2×10×r2
0.1=1/2×10×(100/v)2...........(ii)
From Eqs (i) and (ii), we get
u=700ms1

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