Two parabolas y2=4a(x−l1) and x2=4a(y−l2) always touch one another, the quantities l1 and l2 are both variable. Locus of their point of contact has the equation
A
xy=a2
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B
xy=2a2
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C
xy=4a2
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D
None
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Solution
The correct option is Cxy=4a2 Let P(x1,y1) be point of contact of two parabola. tangents at P of the two parabolas are yy1=2a(x+x1)−4al1 and xx1=2a(x+y1)−4al2 ⇒2ax−yy1=2a(2l1−x1) ......(i) and xx1−2ay=2a(y1−2l2) .....(ii) Clearly (i) and (ii) represent same line ∴2ax1=y12a⇒x1y1=4a2 Hence locus of P is xy=4a2