Two parallel conductors carrying 5A each, repel with a force of 0.25 N $m^{- 1}$ . The distance between them is

4 \times 10^{- 5} m

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3 \times 10^{- 5} m

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2 \times 10^{- 5} m

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1 \times 10^{- 5} m

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Solution

The correct option is C $2 \times 10^{- 5} m$
$\frac{d f}{d l} = \frac{μ_{0} i_{1} i_{2}}{2 π r}$
$0 \cdot 25 = \frac{2 \times 10^{- 7} \times 5 \times 5}{r}$
$r = 2 \times 10^{- 5} m$

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Two parallel conductors carrying 5A each, repel with a force of 0.25 N m−1 . The distance between them is

The correct option is C 2×10−5mdfdl=μ0i1i22πr0⋅25=2×10−7×5×5rr=2×10−5m

Two parallel conductors carrying 5A each, repel with a force of 0.25 N $m^{- 1}$ . The distance between them is

The correct option is C $2 \times 10^{- 5} m$
$\frac{d f}{d l} = \frac{μ_{0} i_{1} i_{2}}{2 π r}$
$0 \cdot 25 = \frac{2 \times 10^{- 7} \times 5 \times 5}{r}$
$r = 2 \times 10^{- 5} m$