Question

Two parallel forces of magnitude $4$ and $6$ newton are acting on a body placed at $4$ m apart.Result-ant will be-

Answer 1

If the forces are in the same direction, then the resultant force will be $10N$ if in opposite direction it will be $2N$.

Let us calculate the position of this force. This can be found by calculating the mean distance of the forces.

Iets take $4N$ force as reference.

so weighted mean$=\frac{\left(0m\right)\times 4N+\left(4m\right)\times 6N)}{4N+6N}=\frac{24}{10}=2.4m$ from $4N$ force