Two parallel glass plates are dipped partly in the liquid of density 'd' keeping them vertical. If the distance between the plates is 'x', surface tension for liquids is T and angle of contact is θ , then rise of liquid between the plates due to capillary will be
Let the width of each plate is b and due to surface tension liquid will rise upto height h then upward force due to surface tension = 2Tbcos θ
Weight of the liquid rises in between the plates = Vdg=(bxh)dg
Equating (i) and (ii) we get, 2Tcos θ=bxhdg
∴h=2Tcos θxdg