Two parallel large thin metal sheets have equaI surface charge densities of 2-56 - 10-3 Cm-3 of opposite signs- The electric field between these sheets is -

The correct option is C 3NC^ 1 The field due to each plate is σ2ϵ_o right due to positive plate and right due to negative plate as well. #160;Hence ...

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Standard XII

Physics

Infinite Sheet

Two parallel ...

Question

Two parallel large thin metal sheets have equaI surface charge densities of $2.56 \times 10^{- 3} C m^{- 3}$ of opposite signs. The electric field between these sheets is :

1.5 N C^{- 1}

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1.5 \times 10^{- 10} N C^{- 1}

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3 N C^{- 1}

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3 \times 10^{- 10} N C^{- 1}

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Solution

The correct option is C $3 N C^{- 1}$

The field due to each plate is $\frac{σ}{2 ϵ_{o}}$ right due to positive plate and right due to negative plate as well.
Hence net electric field $= E = \frac{σ}{2 ϵ_{o}} + \frac{σ}{2 ϵ_{o}}$

Electric field $E = \frac{σ}{ϵ_{o}}$

$⟹ E = \frac{2.56 \times 10^{- 3}}{8.8 \times 10^{- 12}}$

$⟹ E = 3 \times 10^{8} N / C$

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Two parallel large thin metal sheets have equaI surface charge densities of 2.56×10−3Cm−3 of opposite signs. The electric field between these sheets is :

The correct option is C 3NC−1The field due to each plate is σ2ϵo right due to positive plate and right due to negative plate as well.Hence net electric field=E=σ2ϵo+σ2ϵoElectric field E=σϵo⟹E=2.56×10−38.8×10−12⟹E=3×108N/C

Two parallel large thin metal sheets have equaI surface charge densities of $2.56 \times 10^{- 3} C m^{- 3}$ of opposite signs. The electric field between these sheets is :