Question

Two parallel large thin metal sheets have equal surface charge densities $(\sigma =26.4\times {10}^{-12}c/m^2)$ of opposite signs. The electric field between these sheets us :-

• A. 1.5 N/C
• B. $1.5\times {10}^{-10}N/C$
• C. 3 N/c
• D. $3\times {10}^{-10}N/C$

Answer 1

The correct option is A 1.5 N/C

$\sigma =26.4\times {10}^{-12}C/m^2$

Electric field between these sheets

$E=\frac{\sigma }{2{ϵ}_0}$ (using the Gauss law)

$=\frac{26.4\times {10}^{-12}}{2\times 8.854\times {10}^{-12}}$

$=\frac{2.9N/C}{2}\approx \frac{3}{2}N/C$

$=1.5N/C$