Question

Two parallel large thin metal sheets have equal surface charge densities $(\sigma =26.4\times {10}^{-12}{\text{C/m}}^2)$ of opposite signs. The electric field between these sheets is

• A. $1.5\text{N/C}$
• B. $1.5\times {10}^{-10}\text{N/C}$
• C. $3\text{N/C}$
• D. $3\times {10}^{-10}\text{N/C}$

Answer 1

The correct option is C $3\text{N/C}$

Electric field between sheets is given as,
$E=\frac{\sigma }{2{\epsilon }_0}+\frac{\sigma }{2{\epsilon }_0}=\frac{\sigma }{{\epsilon }_0}$
$\therefore E=\frac{26.4\times {10}^{-12}}{8.85\times {10}^{-12}}\simeq 3\text{N/C}$