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Standard XII

Physics

Capacitance of Parallel Plate Capacitor

Two parallel,...

Question

Two parallel, long wires carry currents $i_{1}$ and $i_{2}$ with $i_{1} > i_{2}$ . When the currents are in the same direction, the magnetic field at a point mid way between the wires is $10 μ T$ . If the direction of $i_{2}$ is reverse, the field become $30 μ T$ . The ratio $\frac{i_{1}}{i_{2}}$ is

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Solution

The correct option is C 2
$B_{1} - B_{2} = 10 \times 10^{- 6} T B_{1} + B_{2} = 30 \times 10^{- 6} T \frac{B_{1} + B_{2}}{B_{1} - B_{2}} = \frac{3}{1}; \frac{B_{1}}{B_{2}} = \frac{4}{2} = 2 ∴ \frac{i_{1}}{i_{2}} = 2$

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Similar questions

Q. Two parallel, long wires carry currents i₁ and i₂ with i₁ > i₂. When the currents are in the same direction, the magnetic field at a point midway between the wires is 10 µT. If the direction of i₂ is reversed, the field becomes 30 µT. The ratio i₁/i₂ is
(a) 4
(b) 3
(c) 2
(d) 1

Q. Two parallel long wires carry currents

i_{1}

and

i_{2}

(

i_{1}

i_{2}

). When the currents are in the same direction, the magnetic induction at a point midway between the wires is

10 μ T

. If the direction of

i_{2}

is reversed, the induction becomes

30 μ T

. The ratio of

\frac{i_{1}}{i_{2}}

is :

Q. Two parallel long wires carry currents

i_{1}

and

i_{2}

with

i_{1} > i_{2}

. when the currents are in the same direction, the magnetic field at a point midway between the wires is

10 μ T

. If the direction of

i_{2}

is reversed, the field becomes

30 μ T

. The ratio

\frac{i_{1}}{i_{2}}

Q. Two parallel long wires carry currents

i_{1}

i_{2}

(

i_{1}

i_{2}

) when the currents are in the same direction. The magnetic induction at a point midway between the two wires is

X

. If the direction of

i_{2}

is reversed, the magnetic induction becomes

2 X

, then

i_{1}

i_{2}

is:

Q. A long parallel straight conductors carry

i_{1}

and

i_{2} (i_{1} > i_{2})

. When the currents are in same direction, the magnetic field at a point midway between the wires is

20 μ T

. If the direction of

i_{2}

is reversed, the field becomes

50 μ T .

The ratio of the current

i_{1} / i_{2}

is:

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Two parallel, long wires carry currents i1 and i2 with i1>i2. When the currents are in the same direction, the magnetic field at a point mid way between the wires is 10μT. If the direction of i2 is reverse, the field become 30μT. The ratio i1i2 is

The correct option is C 2B1−B2=10×10−6TB1+B2=30×10−6TB1+B2B1−B2=31;B1B2=42=2∴i1i2=2

The correct option is C 2
$B_{1} - B_{2} = 10 \times 10^{- 6} T B_{1} + B_{2} = 30 \times 10^{- 6} T \frac{B_{1} + B_{2}}{B_{1} - B_{2}} = \frac{3}{1}; \frac{B_{1}}{B_{2}} = \frac{4}{2} = 2 ∴ \frac{i_{1}}{i_{2}} = 2$