Two parallel metal plates are $3 m m$ apart and have a uniform electric field strength $500$ $V m^{- 1}$ between them. The potential difference between the plates is:

15 V

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166.7 V

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16.67 V

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1.5 V

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Solution

The correct option is D $1.5 V$
We know E $= \frac{V}{d}$
or, $V = E . d$ $= 500 \times 3 \times 10^{- 3}$ $= 1500 \times 10^{- 3} v o l t$ $= 1.5 v o l t$

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Two parallel metal plates are 3 mm apart and have a uniform electric field strength 500 Vm−1 between them. The potential difference between the plates is:

The correct option is D 1.5 VWe know E =Vdor, V=E.d =500×3×10−3=1500×10−3 volt=1.5 volt

Two parallel metal plates are $3 m m$ apart and have a uniform electric field strength $500$ $V m^{- 1}$ between them. The potential difference between the plates is:

The correct option is D $1.5 V$
We know E $= \frac{V}{d}$
or, $V = E . d$ $= 500 \times 3 \times 10^{- 3}$ $= 1500 \times 10^{- 3} v o l t$ $= 1.5 v o l t$