Two parallel plate capacitor have their plate area 100 and 500 centimetres square if they have the same charge and potential and the distance between the plates of the first capacitors is. 5 millimetre what is the distance between the plates of the second capacitor

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Solution

Dear Student,

As the charge and Voltage of both the capacitor is same.

We know capacitance of capacitor = charge / potential difference.

$C = \frac{Q}{V} \sin c e Q a n d V f o r b o t h t h e c a p i c a t o r i s s a m e t h e y h a v e s a m e c a p a c i \tan c e . w e k n o w c a p a c i \tan c e c a n a l s o b e g i v e n b y . C = ε \frac{A}{d} (A - a r e a o f p l a t e a n d d - d i s \tan c e b i t w e e n p l a t e) . C_{1} = \frac{A_{1}}{d_{1}} C_{2} = \frac{A_{2}}{d_{2}} . n o w C_{1} = C_{2} . \frac{A_{1}}{d_{1}} = \frac{A_{2}}{d_{2}} . \frac{100}{5} = \frac{500}{d_{2}} . d_{2} = \frac{500 \times 5}{100} = 25 m m . R e g a r d s .$

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