wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two parallel plate capacitors with capacitances C and 2C are joined in parallel and the combination is connected to a battery of potential difference V. If the battery is now removed and a material of dielectric constant K is filled between the plates of capacitor C completely, then what will be the potential difference across the two capacitors?

A
2VK+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3VK+2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
VK+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3VK2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3VK+2

Let the initial potential difference be V

So, the initial charge on first capacitor, q1=CV

Initial charge on second capacitor, q2=2CV

As the battery is disconnected and a dielectric is introduced, the charge will redistribute on the capacitors.

However, as this is an isolated system, charge will remain conserved.

Let, the new potential difference be V which will be the same for both capacitors as they are connected in parallel.

If q1 and q2 are the final charges on the capacitors, then from the conservation of charge

q1+q2=q1+q2

CV+2CV=KCV+2CV

V=3VK+2

Hence, option (c) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parallel Plate Capacitor
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon