Two parallel-plate of capacitor have charges +Q and -Q and potential difference $△ V$ due to charging, Now the capacitor is disconnected then the potential difference and the stored electrical potential energy is:

The potential difference decreases, and the stored electrical potential energy decreases

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The potential difference decreases, and the stored electrical potential energy increases

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The potential difference increases, and the stored electrical potential energy decreases

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The potential difference increases, and the stored electrical potential energy increases

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The potential difference decreases, and the stored electrical potential energy remains unchanged.

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Solution

The correct option is E The potential difference decreases, and the stored electrical potential energy remains unchanged.
When the capacitor is discharged from the battery then the charge cannot go anywhere from the capacitors and thus the energy in it remains constant.

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Two parallel-plate of capacitor have charges +Q and -Q and potential difference △V due to charging, Now the capacitor is disconnected then the potential difference and the stored electrical potential energy is:

The correct option is E The potential difference decreases, and the stored electrical potential energy remains unchanged.When the capacitor is discharged from the battery then the charge cannot go anywhere from the capacitors and thus the energy in it remains constant.

Two parallel-plate of capacitor have charges +Q and -Q and potential difference $△ V$ due to charging, Now the capacitor is disconnected then the potential difference and the stored electrical potential energy is:

The correct option is E The potential difference decreases, and the stored electrical potential energy remains unchanged.
When the capacitor is discharged from the battery then the charge cannot go anywhere from the capacitors and thus the energy in it remains constant.