wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two parallel plates 5cm apart are connected to a 500 V D.C supply. Assuming that an electron starts from rest, its velocity after a nano second is

A
1.56×106m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.66×106m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.76×106m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.86×106m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.76×106m/s
Electric field in the parallel plates =5005×100N/e

104N/c
Force experienced by electron =e104

Acceleration =e104m=104×1.76×1011=1.76×1015 [ em ratio is known ]

So,
Velocity after 109 seconds,
V=v+at[v=0]
V=1.76×1015×109m/s
V=1.76×106m/s
V=1.76×106m/s
So, the answer is option (C).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cathode Ray Experiment
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon