Two parallel plates are 0.03m apart. The electric field intensity between them is 3000 newton per coulomb. Calculate the potential difference between the plates?

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Solution

electric field E =dv/dr
here
E=3000N/C and dr =0.03 m
dv= 3000*0.03
dv=90 V
the potential difference is 90 V

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Two parallel plates are 0.03m apart. The electric field intensity between them is 3000 newton per coulomb. Calculate the potential difference between the plates?

electric field E =dv/dr here E=3000N/C and dr =0.03 m dv= 3000*0.03 dv=90 V the potential difference is 90 V

electric field E =dv/dr
here
E=3000N/C and dr =0.03 m
dv= 3000*0.03
dv=90 V
the potential difference is 90 V