Question

Two particle with equal kinetic energies are having masses in the ratio $1:2$, Then linear momenta will be in the ratio:

• A. $1$
• B. $4$
• C. $0.707$
• D. $2$

Answer 1

The correct option is C $0.707$

$P=\sqrt{2mKE}$

$P_1:P_2=\sqrt{m_{1}K{E}_1:m_{2}K{E}_2}$

$P_1:P_2=1:\sqrt{2}=0.707$