Question

Two particles $A$ and $B$ are connected by a grid rod $AB$. The rod slides along perpendicular rails as shown. The velocity of $A$ to the left is $10m/s$ when $\alpha ={30}^{\circ }$, then what is the velocity of $B$?

• A. $5.8m/s$
• B. $17.3m/s$
• C. $9.8m/s$
• D. $10m/s$

Answer 1

The correct option is B $17.3m/s$

$\left(B\right)$

$v_A,v_B$ be the velocity of A & B

since Length of rod has to be constant so: $v_{A}cos\alpha =v_{B}sin\alpha$

$v_B=v_{A}cot\alpha$

$v_B=10\times \sqrt{3}=17.3$