Two particles A and B are moving with constant velocities v1 and v2. At t = 0, v1 makes an angle θ1 with the line joining A and B and v2 makes an angle θ2 with the line joining A and B. Find their velocity of approach.
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Solution
Velocity of particle A along line AB is VA=v1cosθ1 (towards right)
Velocity of particle B along line AB is VB=v2cosθ2 (towards left)
Velocity of approach Vapproach=VA+VB=v1cosθ1+v2cosθ2