Two particles A and B are moving with uniform velocity as shown in the figure given below at t =0. Find out shortest distance between two particles.
A
2√5m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4√5m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8√5m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8√5m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B4√5m Solving from the frame of B we get tanθ=1020=12 again tanθ=ADCD=AD40=12 ⇒AD=20⇒DO=10⇒BC=10 dshort=BCcosθ=10cosθ=10×2√5=4√5m