Two particles A and B are projected simultaneously with velocities VA=11m/s and VB=15m/s as shown in the figure. Find the time (in seconds) when they collide.
A
1s
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B
2s
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C
4s
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D
3s
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Solution
The correct option is B2s Solving from frame of reference of particle A,
Relative acceleration vertical direction ayBA=0
At the time of collision, relative horizontal displacement of particle B with respect to particle A will be XBA=40m
Now, relative horizontal velocity of B with respect to A will be:- −−→VBA=VB−VA=15sin37∘^i+15cos37∘^j−(−11^i) ∴−−→VBA=9^i+12^j+11^i=20^i+12^j
Applying the condition of collision for particles: XBA=VBAx×t