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Question

Two particles A and B are projected simultaneously with velocities VA=11 m/s and VB=15 m/s as shown in the figure. Find the time (in seconds) when they collide.


A
1 s
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B
2 s
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C
4 s
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D
3 s
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Solution

The correct option is B 2 s
Solving from frame of reference of particle A,
Relative acceleration vertical direction ayBA=0

At the time of collision, relative horizontal displacement of particle B with respect to particle A will be
XBA=40 m

Now, relative horizontal velocity of B with respect to A will be:-
VBA=VBVA=15sin37^i+15cos37^j(11^i)
VBA=9^i+12^j+11^i=20^i+12^j



Applying the condition of collision for particles:
XBA=VBAx×t

t=XBAVBAx=4020=2 s

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