Two particles A and B having different masses are projected from a tower with same speed. A is projected vertically upward and B vertically downward. On reaching the ground.

Velocity of A is greater than that of B

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Velocity of B is greater than that of A

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Both A and B attain the same velocity

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The particle with the larger mass attains higher velocity

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Solution

The correct option is C Both A and B attain the same velocity
$V_{A}^{2} = u^{2} - 2 g (- h) = u 62 + 2 g h$
$V_{b}^{2} = u^{2} + 2 g h = u^{2} + 2 g h$
$V_{A} + V_{B}$ (Attain the same final velocity)

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Two particles A and B having different masses are projected from a tower with same speed. A is projected vertically upward and B vertically downward. On reaching the ground.

The correct option is C Both A and B attain the same velocityV2A=u2−2g(−h)=u62+2ghV2b=u2+2gh=u2+2ghVA+VB (Attain the same final velocity)

The correct option is C Both A and B attain the same velocity
$V_{A}^{2} = u^{2} - 2 g (- h) = u 62 + 2 g h$
$V_{b}^{2} = u^{2} + 2 g h = u^{2} + 2 g h$
$V_{A} + V_{B}$ (Attain the same final velocity)