Question

# Two particles A and B, having opposite charges $$2.0\times 10^{-6}$$C and $$-2.0\times 10^{-6}$$C, are placed at a separation of $$1.0$$cm. Write down the electric dipole moment of this pair.

Solution

## The distance between the charges is $$1.0\ cm$$The magnitude of two charges is $$2\times 10^{-6}\ C$$The Dipole moment is given as:$$=q\times l$$(where $$q=$$ magnitude of charge $$l=$$separation between the charges)Substitute the values in above expression:$$=2\times 10^{-6}\times 10^{-2}cm$$$$=2\times 10^{-8}cm$$.PhysicsNCERTStandard XII

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