Question

Two particles A and B move on a horizontal surface with constant velocities as shown in the figure. If the initial distance of separation between them is $10m$ at $t=0$, then find distance between them at $t=2sec$ .

• A. $37.4$ units
• B. $38.4$ units
• C. $35.4$ units
• D. $39.4$ units

Answer 1

Answer: (A)

$37.4$ units

Relative velocity of A wrt B is.

$V_{a}Cos\theta -V_{b}Cos\theta$ in x direction

Similarly in y direction $V_{a}Sin\theta -V_{b}Sin\theta$.

After 2 sec position of A wrt B will be $-10+2\times (10-5)=0$in x and $2\times (10+5\sqrt{3})=37.4meter.$