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Standard XII

Physics

Relation between Linear and Angular Speed

Two particles...

Question

Two particles A and B of equal mass are located at some distance from each other. Particle A is at rest while B moves away from A at speed v. What happens to the center of mass of the two particles?

It does not move

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It moves with a speed v away from A

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It moves with a speed away from A

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It moves with a speed towards A

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Solution

The correct option is C
It moves with a speed away from A

${\to v}_{c m} = \frac{m_{1} {\to v}_{1} + m_{2} {\to v}_{2}}{m_{1} + m_{2}} = \frac{m (0) + m (\to v)}{2 m} = \frac{v}{2} m / s e c i n t h e d i r e c t i o n o f p a r t i c l e^{'} B^{'} .$

$∴ i t m o v e s a t a s p e e d o f \frac{v}{2} a w a y f r o m^{'} A^{'}$

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Two particles A and B of equal mass are located at some distance from each other. Particle A is at rest while B moves away from A at speed v. What happens to the center of mass of the two particles?

The correct option is C It moves with a speed away from A →vcm=m1→v1+m2→v2m1+m2=m(0)+m(→v)2m=v2m/secinthedirectionofparticle′B′. ∴itmovesataspeedofv2awayfrom′A′