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Question

Two particles A and B of masses mA and mB respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speed of the particles are vA and vB respectively, and the trajectories are as shown in the figure. Then

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A
mAvA<mBvB
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B
mAvA>mBvB
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C
mA<mB and vA<vB
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D
mA=mB and vA=vB
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Solution

The correct option is B mAvA>mBvB
When a charged particle is moving at right angle to the magnetic field, then a force acts on it which behaves as a centripetal force and moves the particle in circular path.
But, r=pqB
Radius of B is less than radius of A.
rB<rA
pB<pA
mBvB<mAvA
mAvA>mBvB.

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