Question

Two particles A & B are projected horizontally in the same direction from same height at $4\text{m/s}$ & $7\text{m/s}$. If they hit the ground at a distance of $18\text{m}$from each other, then find the height from which they were projected.

Answer 1

Answer (4)


Let Time of flight be ${}^{\prime }{T}^{\prime },7T-4T=3T$
Thus $3T=18$
$3\sqrt{\frac{2h}{g}}=18$
$\frac{2h}{g}=36$
$h=180\text{m}$