Question

Two Particles are dropped simultaneously from the top of a tall building. Particle 1 has mass $M_1$ and particle 2 has mass $M_2$. Find out the ratio of their momentum just before they hit the ground? Neglect the air resistance.

• A. $\frac{\sqrt{M_1}}{M_2}$
• B. $\frac{M_1}{M_2}$
• C. ${\left(\frac{M_1}{M_2}\right)}^2$
• D. $1$
• E. None of the above

Answer 1

The correct option is B $\frac{M_1}{M_2}$

Initial velocity of the particle is zero i.e $u=0$ m/s

$\therefore$ Velocity with which it hits the ground $v=\sqrt{2gh}$ where $h$ is the height of building

$⟹$ $v_1=v_2$

Thus ratio of momentum $\frac{P_1}{P_2}=\frac{M_1{v}_1}{M_2{v}_2}=\frac{M_1}{M_2}$