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Question

Two particles are in S.H.M, of same amplitude 'a', same frequency 'f', along the same straight line about the same mean position. The maximum distance between the two particles is a2. The initial phase difference between the particles is :

A
π2
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B
zero
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C
π3
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D
π6
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Solution

The correct option is A π2
x1=Asin(wt+ϕ1)

x2=Asin(wt+ϕ2)

|x1x2|=2Asin[wt+ϕ1+ϕ22]cosϕ1ϕ22

|x1x2|maxsin[wt+ϕ1+ϕ22]
a2=2a×1×cos[ϕ1ϕ22]

ϕ1ϕ22=π4Δϕ=π2

Hence "A"

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