Question

Two particles are in SHM in parallel straight lines close to each other. Amplitude $A$ and time period $T$ of both the particles are equal. At $t=0$, one particle is at displacement $x_1=+A$ and other at $x_2=-\frac{A}{2}$ an they are approaching towards each other, after what time they will cross each other?

• A. $T/3$
• B. $T/4$
• C. $5T/6$
• D. $T/6$

Answer 1

The correct option is D $T/6$

Angle covered to meet $\theta ={60}^0=\frac{\pi }{3}rad$

If they cross each other at time $t$,

Then,

$t=\frac{\theta }{2\pi }=\frac{\pi }{3\times 2\pi }T=\frac{T}{6}$.