Question

Two particles are projected from the ground simultaneously with speeds of $20\text{m/s}$ at angles of ${30}^{\circ }$ and ${60}^{\circ }$ respectively with the horizontal in the same direction. The distance between them when both of them strike the ground is $(g$ = $10{\text{m/s}}^2)$

Answer 1

As we know,
The horizontal range for two projectiles, projected with the same initial speed at complementary angles, is equal.

In our case, we have two given complementary angles as ${30}^{\circ }$and ${60}^{\circ }$.
So the range will be the same in both cases.

Therefore, the distance between them when both of them strike the ground is $0\text{m}$.

Hence, option $\left(\text{d}\right)$ is correct.