Two particles are projected with the same velocity but at angles of projection (45o−θ) and (45o+θ) to have maximum range. Then their horizontal ranges are in the ratio of
A
1:2
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B
2:1
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C
1:1
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D
1:4
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Solution
The correct option is C1:1 Range, R=u2sin2θg So,R1=u2sin(2(45−θ))g=u2cos2θg R2=u2sin(2(45+θ))g=u2cos2θg Hence, R1=R2