Two particles at t=0are thrown horizontally in opposite directions from the same point from a height h with velocities 4ms−1 and 3ms−1. Find the time when their velocities are perpendicular.
A
0.15s
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B
0.25s
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C
0.35s
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D
none of these
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Solution
The correct option is D0.35s →V1=−4^i−gt^j and →V2=3^i−gt^j are the velocities at any instant. For velocities to be perpendicular →V1.→V2=0 →V1.→V2=0⟹t=√12g2=0.35s