Question

Two particles each of mass $m$ are moving in the horizontal circle with same angular speed. If both the strings are of same length then the ratio of tension is string $\frac{T_1}{T_2}$ is:

• A. $\frac{3}{2}$
• B. $3$
• C. $2$
• D. $\frac{1}{3}$

Answer 1

The correct option is A $\frac{3}{2}$

Correct option is A

$t_2=m\left(2l\right)w^2-----------\left(1\right)$

$t_1-t_2=ml{w}^2------------\left(2\right)$

Ratio of both equation (1)&(2)

$\frac{t_1-t_2}{t_2}=\frac{1}{2}$

$2(t_1-t_2)=t_2$

$2t_1-2t_2=t_2$

$2t_1=t_2+2t_2$

$2t_1=3t_2$

$\frac{t_1}{t_2}=\frac{3}{2}$