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Question

# Two particles execute SHM of same amplitude and frequency on straight lines. They pass one another when moving in opposite directions each time when their displacements is half of the amplitude. The phase difference between them is

A
0
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B
2π3
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C
π
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D
π6
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Solution

## The correct option is B 2π3Let A and B particle is moving in the circular path with uniform velocity in a clockwise direction, Motion of projection of particle on the XY line will be in SHM.According to question,Particle is meeting at a2 and moving in the opposite direction, So Location of particle will be on A, B as given in the diagram.Let Particle A making angle θ1 and particle B will be θ2 then Path diffrence, ϕ=θ1+θ2.......(1)θ1=cos−1a/2a=60∘=π3θ2=cos−1a/2a=60∘=π3From equation (1)ϕ=2π3

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