CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

two particles execute SHM on same straight line with same position,same time period 6 second and same amplitude 5 cm. Both the particle start SHM from their mean position (in same direction) with a time gap of 1 sec. Find the maximum separation between the two particles during their motion:

A
2 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2 cm
Given,
Two particles executes SHM on same straight line with same position
Same time period =6s
Same amplitude =5cm
Both the particle starts SHM from their mean position(in same direction)
Time gap=1sec
Finding maximum
separation between the two particles during their motion
T=2πlg6=2πl10(3π)2×10=ll=105=2cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Periodic Motion and Oscillation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon