Two particles have equal masses of 5.0 g each and opposite charges of +4×10−5C and −4×10−5C. They are released with a separation of 1.0 m between them. Find the speeds of the particles when the separation is reduced to 50 cm.
Open in App
Applying conservation of momentum by initial and final stage Pi=0Pf=mv1+mv2Pf=Piv1=−v2...(1) Now applying energy conservation by two points KEi+(P.E)i=KEf+(P.E)f mv21−mv212=kq2(2r−1r) mv21=15410 v1=53.66m/s=−v2.