CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relative Velocity in 2D

Two particles...

Question

Two particles having position vectors $_{1} = 3^i + 5^j$ m and $_{2} = - 5^i + 3^j$ m are moving with velocities $_{1} = 4^i + 3^j$ m/s and $_{2} = - a^i + 4^j$ m/s. If they collide after $2$ seconds, the value of $a$ is:

A

- 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

- 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

- 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

- 8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $- 8$
For collision, their position vectors at $t = 2$ should be same. Hence
$3^i + 5^j + 2 (4^i + 3^j) = - 5^i + 3^j + 2 (- a^i + 4^j)$
$⟹ 11^i + 11^j = - (5 + 2 a)^i + 11^j$
$⟹ 5 + 2 a = - 11$
$⟹ a = - 8$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Two particles having position vectors

_{1} = (3^i + 5^j) m

_{2} = (- 5^i + 3^j) m

are moving with velocities

_{1} = (4^i - 4^j) {ms}^{- 1}

_{2} = (a^i - 3^j) {ms}^{- 1}

. If they collide after

2 s

, the value of the constant '

a

Q. Two particles

1

2

are moving with constant velocities

{\to v}_{1} = 4^i - 3^j m/s

{\to v}_{2} = b^i -^j m/s

respectively. The position vectors of the particles at time

t = 0

{\to r}_{1} = 5^i + 2^j m

{\to r}_{2} = - 4^i - 4^j m

. If they collide, which of the following is correct. (

b

Q. Two particles having position vectors

\to r = (3 \to i + 5 j) m

{\to r}_{2} = (- 5 i + 3 j) m

are moving with velocities

{\to V}_{1} = (4^i - 4^j) m s^{- 1}

{\to V}_{2} = (a^i - 3^j) m s^{- 1}

. If they collide after

2

seconds , the value of

a

Q. Two particle A and B having initial position

(0, 0)

(\frac{48}{5}, \frac{36}{5}) m

. Their initial velocity is

(4^i + 3^j)

(- 4^i - 3^j)

m/s respectively. Both have same acceleration

\to a = - 9^j

^{2}

. Then, two particles will collide after time

Q. Two particles, 1 and 2, move with constant velocities

v_{1}

v_{2}

. At the initial moment their radius vectors are equal to

r_{1}

r_{2}

. The relation between these four vectors for the particles to collide is

\frac{(_{1} -_{2})}{|_{1} -_{2} |} = x \frac{(_{2} -_{1})}{|_{2} -_{1} |}

x

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Motion in 2D

PHYSICS

Watch in App

explore_more_icon

Explore more

Relative Velocity in 2D

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon