Two particles of equal mass are revolving with the same linear speed on circular paths of radii $r_{1}$ and $r_{2}$ . How much will the ratio of the centripetal force acting on them be?

\frac{r_{2}}{r_{1}}

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\sqrt{\frac{r_{2}}{r_{1}}}

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{(\frac{r_{1}}{r_{2}})}^{2}

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{(\frac{r_{2}}{r_{1}})}^{2}

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Solution

The correct option is C $\frac{r_{2}}{r_{1}}$
Centripetal force acting on a body of mass 'm' revolving with radius 'r' is
$F = \frac{m v^{2}}{r}$
$F_{1} = \frac{m v^{2}}{r_{1}}$
$F_{2} = \frac{m v^{2}}{r_{2}}$
Velocities are same for both the bodies.
Hence $\frac{F_{1}}{F_{2}} = \frac{r_{2}}{r_{1}}$

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Two particles of equal mass are revolving with the same linear speed on circular paths of radii r1 and r2. How much will the ratio of the centripetal force acting on them be?

The correct option is C r2r1Centripetal force acting on a body of mass 'm' revolving with radius 'r' isF=mv2rF1=mv2r1F2=mv2r2Velocities are same for both the bodies.Hence F1F2=r2r1

Two particles of equal mass are revolving with the same linear speed on circular paths of radii $r_{1}$ and $r_{2}$ . How much will the ratio of the centripetal force acting on them be?