Two particles of equal mass have initial velocities 2- ms-1 and 2- ms-1- First particle has a constant acceleration - - - ms-1 while the acceleration of the second particle is always zero- The centre of mass of the two particles moves in -

The correct option is D Straight lineVelocity of center of mass is given by: v = v_1 m_1 + v_2 m_2m_1 + m_2 = i + j Acceleration of center of mass is given ...

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Byju's Answer

Standard XII

Physics

Phasors

Two particles...

Question

Two particles of equal mass have initial velocities $2^i m s^{- 1} a n d 2^j m s^{- 1}$ . First particle has a constant acceleration $(^i +^j) m s^{- 1}$ while the acceleration of the second particle is always zero. The centre of mass of the two particles moves in :

Circle

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Parabola

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Ellipse

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Straight line

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Solution

The correct option is D Straight line
Velocity of center of mass is given by:
$v = \frac{v_{1} m_{1} + v_{2} m_{2}}{m_{1} + m_{2}} = i + j$
Acceleration of center of mass is given by:
$a = \frac{a_{1} m_{1} + a_{2} m_{2}}{m_{1} + m_{2}} = \frac{1}{2} (i + j)$
Acceleration and velocity both have the same direction, hence the body moves along the same line (i+j).
Hence it moves in a straight line.
Option D is correct.

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