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Question

Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other forces act on them. When the velocity of approach of the two particles is 2 m/s, their centre of mass has a velocity of 0.5 m/s. When the velocity of approach becomes 3 m/s, the velocity of the centre of mass of the system of particles is

A
0.75 m/s
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B
0.5 m/s
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C
1.25 m/s
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D
1.5 m/s
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Solution

The correct option is B 0.5 m/s
Mutual forces of attraction are internal forces. The sum of internal forces for a system is always zero.


Hence, there is no net external force acting on the system.
Fext=0
From Newton's second law,
Fext=macom
acom=0
vcom=constant
Therefore, velocity of the centre of mass will not change. Velocity of centre of mass will remain constant at 0.5 m/s throughout the motion.

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