Question

Two particles of mass $1kg$ and $0.5kg$ are moving in the same direction with speed of $2m/s$ and $6m/s$ respectively on a smooth horizontal surface. The speed of centre of mass of the system is then

Answer 1

Given that,

First particle of mass $m_1=1kg$

Second particle of mass $m_2=0.5kg$

Speed of first particle $v_1=2m/s$

Speed of second particle $v_2=6m/s$

We know that,

Speed of center of mass

$v_{cm}=\frac{m_1{v}_1+m_2{v}_2}{m_1+m_2}$

$v_{cm}=\frac{1\times 2+0.5\times 6}{1+0.5}$

$v_{cm}=3.33m/s$.

Hence, the speed of center of mass is $3.33m/s$