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Question

Two particles of mass MA and MB and there velocities are VA and VB respectively collides. After collision they inter changes their velocities then ratio of MAMB is?

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Solution

Before collision momentum =ρ1=MAVA+MBVB
after collision momentum u ρ2=MAVB+MBVA
momentum is conserve ρ1=ρ2
MAVA+MBVB=MBVA+MAVB
divide both side by MB
MAMBVA+VB=VA+MAMBVBMAMB(VAVB)=(VAVB)
clear that MAMB=1

954758_693669_ans_89856987a31d49ec921e3a24775e5600.JPG

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