Two particles of mass m1 and m2 in projectile motion have velocities v1 and v2 respectively at time t=0 . They collide at time t1 . Their velocities become v1' and v2' at time 2t1 while still moving in air. The value of |(m1v1'+ m2v2')-(m1v1 + m2v2')|

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Q. Two particles of masses

m_{1}

and

m_{2}

in projectile motion have velocities

{¯ ¯ ¯ v}_{1}

and

{¯ ¯ ¯ v}_{2}

respectively at time

t = 0

. They strike at time

t_{0}

and their velocities become

{^{'}}_{1}

and

{^{'}}_{2}

at time

2 t_{0}

while still moving in air. The value of

∣ ∣ (m_{1} {^{'}}_{1} + m_{2} {^{'}}_{2}) - (m_{1} {¯ ¯ ¯ v}_{1} + m_{2} {¯ ¯ ¯ v}_{2}) ∣ ∣

is :

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What is M1V1=M2V2 different from M1=M2V2/(V1+V2)and N1V1=N2V2

A nucleus moving with a velocity $\to v$ emits an $α$ -p article. Let the velocities of the $α$ -particle and the remaining nucleus be $_{1}$ and $_{2}$ and their masses be $m_{1}$ , and $m_{2}$ .

Q. Two satellite having masses

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and

M_{2}

(M_{1} = \frac{M_{2}}{2})

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v_{1}

and

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