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Question

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation, find the initial accelerations of the two particles.

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Solution

Given mass m1=1kg and m2=2kg, separation d=50cm=0.5m
The gravitational forces acting between them, F=Gm1m2d2
Acceleration of particle of mass m1, am1=Fm1=Gm2d2=6.67×1011×20.52=5.336×1010m/s2

Acceleration of particle of mass m2, am2=Fm2=Gm1d2=6.67×1011×10.52=2.668×1010m/s2

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