Two particles of masses 1 kg and 3 kg have position vectors 2-3-4k- and 2-3-4k- respectively- The centre of mass has a position vector-

The correct option is C 2î+3ĵ+4k̂ r⃗_⃗1⃗=2î+3ĵ+4k̂ #160; #160; #160; #160; #160; #160; r⃗_⃗2⃗=2î+3ĵ+4k̂ 1 kg #160; ...

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Byju's Answer

Standard XII

Physics

Displacement of COM:Application

Two particles...

Question

Two particles of masses 1 kg and 3 kg have position vectors $2^i + 3^j + 4^k$ and $2^i + 3^j + 4^k$ respectively. The centre of mass has a position vector:

^i + 3^j - 2^k

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-^i - 3^j - 2^k

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-^i + 3^j + 2^k

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2^i + 3^j + 4^k

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Solution

The correct option is C $2^i + 3^j + 4^k$
$_{1} = 2^i + 3^j + 4^k$ $_{2} = 2^i + 3^j + 4^k$
$1 k g$ $2 k g$
$_{C O M} = \frac{M_{1} r_{1} + M_{2}_{2}}{M_{1} + M_{2}}$
$= \frac{1 (2^i + 3^j + 4^k) + 2 (2^i + 3^j + 4^k)}{1 + 2}$
$= \frac{6^i + 9^j + 12^k}{3}$
$= 2^i + 3^j + 4^k$

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Two particles of masses 1 kg and 3 kg have position vectors 2^i+3^j+4^k and 2^i+3^j+4^k respectively. The centre of mass has a position vector:

The correct option is C 2^i+3^j+4^k→r1=2^i+3^j+4^k →r2=2^i+3^j+4^k1 kg 2 kg→rCOM=M1r1+M2→r2M1+M2=1(2^i+3^j+4^k)+2(2^i+3^j+4^k)1+2=6^i+9^j+12^k3=2^i+3^j+4^k

Two particles of masses 1 kg and 3 kg have position vectors $2^i + 3^j + 4^k$ and $2^i + 3^j + 4^k$ respectively. The centre of mass has a position vector:

The correct option is C $2^i + 3^j + 4^k$
$_{1} = 2^i + 3^j + 4^k$ $_{2} = 2^i + 3^j + 4^k$
$1 k g$ $2 k g$
$_{C O M} = \frac{M_{1} r_{1} + M_{2}_{2}}{M_{1} + M_{2}}$
$= \frac{1 (2^i + 3^j + 4^k) + 2 (2^i + 3^j + 4^k)}{1 + 2}$
$= \frac{6^i + 9^j + 12^k}{3}$
$= 2^i + 3^j + 4^k$